3.6.89 \(\int \frac {\cot ^{\frac {5}{2}}(c+d x) (A+B \tan (c+d x))}{a+b \tan (c+d x)} \, dx\) [589]

3.6.89.1 Optimal result
3.6.89.2 Mathematica [A] (verified)
3.6.89.3 Rubi [A] (warning: unable to verify)
3.6.89.4 Maple [B] (verified)
3.6.89.5 Fricas [B] (verification not implemented)
3.6.89.6 Sympy [F(-1)]
3.6.89.7 Maxima [A] (verification not implemented)
3.6.89.8 Giac [F]
3.6.89.9 Mupad [F(-1)]

3.6.89.1 Optimal result

Integrand size = 33, antiderivative size = 325 \[ \int \frac {\cot ^{\frac {5}{2}}(c+d x) (A+B \tan (c+d x))}{a+b \tan (c+d x)} \, dx=\frac {(b (A-B)-a (A+B)) \arctan \left (1-\sqrt {2} \sqrt {\cot (c+d x)}\right )}{\sqrt {2} \left (a^2+b^2\right ) d}-\frac {(b (A-B)-a (A+B)) \arctan \left (1+\sqrt {2} \sqrt {\cot (c+d x)}\right )}{\sqrt {2} \left (a^2+b^2\right ) d}-\frac {2 b^{5/2} (A b-a B) \arctan \left (\frac {\sqrt {a} \sqrt {\cot (c+d x)}}{\sqrt {b}}\right )}{a^{5/2} \left (a^2+b^2\right ) d}+\frac {2 (A b-a B) \sqrt {\cot (c+d x)}}{a^2 d}-\frac {2 A \cot ^{\frac {3}{2}}(c+d x)}{3 a d}+\frac {(a (A-B)+b (A+B)) \log \left (1-\sqrt {2} \sqrt {\cot (c+d x)}+\cot (c+d x)\right )}{2 \sqrt {2} \left (a^2+b^2\right ) d}-\frac {(a (A-B)+b (A+B)) \log \left (1+\sqrt {2} \sqrt {\cot (c+d x)}+\cot (c+d x)\right )}{2 \sqrt {2} \left (a^2+b^2\right ) d} \]

output
-2*b^(5/2)*(A*b-B*a)*arctan(a^(1/2)*cot(d*x+c)^(1/2)/b^(1/2))/a^(5/2)/(a^2 
+b^2)/d-2/3*A*cot(d*x+c)^(3/2)/a/d-1/2*(b*(A-B)-a*(A+B))*arctan(-1+2^(1/2) 
*cot(d*x+c)^(1/2))/(a^2+b^2)/d*2^(1/2)-1/2*(b*(A-B)-a*(A+B))*arctan(1+2^(1 
/2)*cot(d*x+c)^(1/2))/(a^2+b^2)/d*2^(1/2)+1/4*(a*(A-B)+b*(A+B))*ln(1+cot(d 
*x+c)-2^(1/2)*cot(d*x+c)^(1/2))/(a^2+b^2)/d*2^(1/2)-1/4*(a*(A-B)+b*(A+B))* 
ln(1+cot(d*x+c)+2^(1/2)*cot(d*x+c)^(1/2))/(a^2+b^2)/d*2^(1/2)+2*(A*b-B*a)* 
cot(d*x+c)^(1/2)/a^2/d
 
3.6.89.2 Mathematica [A] (verified)

Time = 1.76 (sec) , antiderivative size = 272, normalized size of antiderivative = 0.84 \[ \int \frac {\cot ^{\frac {5}{2}}(c+d x) (A+B \tan (c+d x))}{a+b \tan (c+d x)} \, dx=-\frac {\sqrt {\cot (c+d x)} \left (-\frac {6 \sqrt {2} (b (-A+B)+a (A+B)) \left (\arctan \left (1-\sqrt {2} \sqrt {\tan (c+d x)}\right )-\arctan \left (1+\sqrt {2} \sqrt {\tan (c+d x)}\right )\right )}{a^2+b^2}+\frac {24 b^{5/2} (-A b+a B) \arctan \left (\frac {\sqrt {b} \sqrt {\tan (c+d x)}}{\sqrt {a}}\right )}{a^{5/2} \left (a^2+b^2\right )}-\frac {3 \sqrt {2} (a (A-B)+b (A+B)) \left (\log \left (1-\sqrt {2} \sqrt {\tan (c+d x)}+\tan (c+d x)\right )-\log \left (1+\sqrt {2} \sqrt {\tan (c+d x)}+\tan (c+d x)\right )\right )}{a^2+b^2}+\frac {8 A}{a \tan ^{\frac {3}{2}}(c+d x)}+\frac {24 (-A b+a B)}{a^2 \sqrt {\tan (c+d x)}}\right ) \sqrt {\tan (c+d x)}}{12 d} \]

input
Integrate[(Cot[c + d*x]^(5/2)*(A + B*Tan[c + d*x]))/(a + b*Tan[c + d*x]),x 
]
 
output
-1/12*(Sqrt[Cot[c + d*x]]*((-6*Sqrt[2]*(b*(-A + B) + a*(A + B))*(ArcTan[1 
- Sqrt[2]*Sqrt[Tan[c + d*x]]] - ArcTan[1 + Sqrt[2]*Sqrt[Tan[c + d*x]]]))/( 
a^2 + b^2) + (24*b^(5/2)*(-(A*b) + a*B)*ArcTan[(Sqrt[b]*Sqrt[Tan[c + d*x]] 
)/Sqrt[a]])/(a^(5/2)*(a^2 + b^2)) - (3*Sqrt[2]*(a*(A - B) + b*(A + B))*(Lo 
g[1 - Sqrt[2]*Sqrt[Tan[c + d*x]] + Tan[c + d*x]] - Log[1 + Sqrt[2]*Sqrt[Ta 
n[c + d*x]] + Tan[c + d*x]]))/(a^2 + b^2) + (8*A)/(a*Tan[c + d*x]^(3/2)) + 
 (24*(-(A*b) + a*B))/(a^2*Sqrt[Tan[c + d*x]]))*Sqrt[Tan[c + d*x]])/d
 
3.6.89.3 Rubi [A] (warning: unable to verify)

Time = 1.73 (sec) , antiderivative size = 286, normalized size of antiderivative = 0.88, number of steps used = 26, number of rules used = 25, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.758, Rules used = {3042, 4064, 3042, 4090, 27, 3042, 4130, 27, 3042, 4136, 3042, 4017, 25, 27, 1482, 1476, 1082, 217, 1479, 25, 27, 1103, 4117, 73, 218}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {\cot ^{\frac {5}{2}}(c+d x) (A+B \tan (c+d x))}{a+b \tan (c+d x)} \, dx\)

\(\Big \downarrow \) 3042

\(\displaystyle \int \frac {\cot (c+d x)^{5/2} (A+B \tan (c+d x))}{a+b \tan (c+d x)}dx\)

\(\Big \downarrow \) 4064

\(\displaystyle \int \frac {\cot ^{\frac {5}{2}}(c+d x) (A \cot (c+d x)+B)}{a \cot (c+d x)+b}dx\)

\(\Big \downarrow \) 3042

\(\displaystyle \int \frac {\left (-\tan \left (c+d x+\frac {\pi }{2}\right )\right )^{5/2} \left (B-A \tan \left (c+d x+\frac {\pi }{2}\right )\right )}{b-a \tan \left (c+d x+\frac {\pi }{2}\right )}dx\)

\(\Big \downarrow \) 4090

\(\displaystyle -\frac {2 \int \frac {3 \sqrt {\cot (c+d x)} \left ((A b-a B) \cot ^2(c+d x)+a A \cot (c+d x)+A b\right )}{2 (b+a \cot (c+d x))}dx}{3 a}-\frac {2 A \cot ^{\frac {3}{2}}(c+d x)}{3 a d}\)

\(\Big \downarrow \) 27

\(\displaystyle -\frac {\int \frac {\sqrt {\cot (c+d x)} \left ((A b-a B) \cot ^2(c+d x)+a A \cot (c+d x)+A b\right )}{b+a \cot (c+d x)}dx}{a}-\frac {2 A \cot ^{\frac {3}{2}}(c+d x)}{3 a d}\)

\(\Big \downarrow \) 3042

\(\displaystyle -\frac {\int \frac {\sqrt {-\tan \left (c+d x+\frac {\pi }{2}\right )} \left ((A b-a B) \tan \left (c+d x+\frac {\pi }{2}\right )^2-a A \tan \left (c+d x+\frac {\pi }{2}\right )+A b\right )}{b-a \tan \left (c+d x+\frac {\pi }{2}\right )}dx}{a}-\frac {2 A \cot ^{\frac {3}{2}}(c+d x)}{3 a d}\)

\(\Big \downarrow \) 4130

\(\displaystyle -\frac {-\frac {2 \int \frac {-B \cot (c+d x) a^2-\left (A a^2+b B a-A b^2\right ) \cot ^2(c+d x)+b (A b-a B)}{2 \sqrt {\cot (c+d x)} (b+a \cot (c+d x))}dx}{a}-\frac {2 (A b-a B) \sqrt {\cot (c+d x)}}{a d}}{a}-\frac {2 A \cot ^{\frac {3}{2}}(c+d x)}{3 a d}\)

\(\Big \downarrow \) 27

\(\displaystyle -\frac {-\frac {\int \frac {-B \cot (c+d x) a^2-\left (A a^2+b B a-A b^2\right ) \cot ^2(c+d x)+b (A b-a B)}{\sqrt {\cot (c+d x)} (b+a \cot (c+d x))}dx}{a}-\frac {2 (A b-a B) \sqrt {\cot (c+d x)}}{a d}}{a}-\frac {2 A \cot ^{\frac {3}{2}}(c+d x)}{3 a d}\)

\(\Big \downarrow \) 3042

\(\displaystyle -\frac {-\frac {\int \frac {B \tan \left (c+d x+\frac {\pi }{2}\right ) a^2+\left (-A a^2-b B a+A b^2\right ) \tan \left (c+d x+\frac {\pi }{2}\right )^2+b (A b-a B)}{\sqrt {-\tan \left (c+d x+\frac {\pi }{2}\right )} \left (b-a \tan \left (c+d x+\frac {\pi }{2}\right )\right )}dx}{a}-\frac {2 (A b-a B) \sqrt {\cot (c+d x)}}{a d}}{a}-\frac {2 A \cot ^{\frac {3}{2}}(c+d x)}{3 a d}\)

\(\Big \downarrow \) 4136

\(\displaystyle -\frac {-\frac {\frac {\int \frac {a^2 (A b-a B)-a^2 (a A+b B) \cot (c+d x)}{\sqrt {\cot (c+d x)}}dx}{a^2+b^2}+\frac {b^3 (A b-a B) \int \frac {\cot ^2(c+d x)+1}{\sqrt {\cot (c+d x)} (b+a \cot (c+d x))}dx}{a^2+b^2}}{a}-\frac {2 (A b-a B) \sqrt {\cot (c+d x)}}{a d}}{a}-\frac {2 A \cot ^{\frac {3}{2}}(c+d x)}{3 a d}\)

\(\Big \downarrow \) 3042

\(\displaystyle -\frac {-\frac {\frac {\int \frac {(A b-a B) a^2+(a A+b B) \tan \left (c+d x+\frac {\pi }{2}\right ) a^2}{\sqrt {-\tan \left (c+d x+\frac {\pi }{2}\right )}}dx}{a^2+b^2}+\frac {b^3 (A b-a B) \int \frac {\tan \left (c+d x+\frac {\pi }{2}\right )^2+1}{\sqrt {-\tan \left (c+d x+\frac {\pi }{2}\right )} \left (b-a \tan \left (c+d x+\frac {\pi }{2}\right )\right )}dx}{a^2+b^2}}{a}-\frac {2 (A b-a B) \sqrt {\cot (c+d x)}}{a d}}{a}-\frac {2 A \cot ^{\frac {3}{2}}(c+d x)}{3 a d}\)

\(\Big \downarrow \) 4017

\(\displaystyle -\frac {-\frac {\frac {2 \int -\frac {a^2 (A b-a B-(a A+b B) \cot (c+d x))}{\cot ^2(c+d x)+1}d\sqrt {\cot (c+d x)}}{d \left (a^2+b^2\right )}+\frac {b^3 (A b-a B) \int \frac {\tan \left (c+d x+\frac {\pi }{2}\right )^2+1}{\sqrt {-\tan \left (c+d x+\frac {\pi }{2}\right )} \left (b-a \tan \left (c+d x+\frac {\pi }{2}\right )\right )}dx}{a^2+b^2}}{a}-\frac {2 (A b-a B) \sqrt {\cot (c+d x)}}{a d}}{a}-\frac {2 A \cot ^{\frac {3}{2}}(c+d x)}{3 a d}\)

\(\Big \downarrow \) 25

\(\displaystyle -\frac {-\frac {\frac {b^3 (A b-a B) \int \frac {\tan \left (c+d x+\frac {\pi }{2}\right )^2+1}{\sqrt {-\tan \left (c+d x+\frac {\pi }{2}\right )} \left (b-a \tan \left (c+d x+\frac {\pi }{2}\right )\right )}dx}{a^2+b^2}-\frac {2 \int \frac {a^2 (A b-a B-(a A+b B) \cot (c+d x))}{\cot ^2(c+d x)+1}d\sqrt {\cot (c+d x)}}{d \left (a^2+b^2\right )}}{a}-\frac {2 (A b-a B) \sqrt {\cot (c+d x)}}{a d}}{a}-\frac {2 A \cot ^{\frac {3}{2}}(c+d x)}{3 a d}\)

\(\Big \downarrow \) 27

\(\displaystyle -\frac {-\frac {\frac {b^3 (A b-a B) \int \frac {\tan \left (c+d x+\frac {\pi }{2}\right )^2+1}{\sqrt {-\tan \left (c+d x+\frac {\pi }{2}\right )} \left (b-a \tan \left (c+d x+\frac {\pi }{2}\right )\right )}dx}{a^2+b^2}-\frac {2 a^2 \int \frac {A b-a B-(a A+b B) \cot (c+d x)}{\cot ^2(c+d x)+1}d\sqrt {\cot (c+d x)}}{d \left (a^2+b^2\right )}}{a}-\frac {2 (A b-a B) \sqrt {\cot (c+d x)}}{a d}}{a}-\frac {2 A \cot ^{\frac {3}{2}}(c+d x)}{3 a d}\)

\(\Big \downarrow \) 1482

\(\displaystyle -\frac {-\frac {\frac {b^3 (A b-a B) \int \frac {\tan \left (c+d x+\frac {\pi }{2}\right )^2+1}{\sqrt {-\tan \left (c+d x+\frac {\pi }{2}\right )} \left (b-a \tan \left (c+d x+\frac {\pi }{2}\right )\right )}dx}{a^2+b^2}-\frac {2 a^2 \left (\frac {1}{2} (a (A-B)+b (A+B)) \int \frac {1-\cot (c+d x)}{\cot ^2(c+d x)+1}d\sqrt {\cot (c+d x)}+\frac {1}{2} (b (A-B)-a (A+B)) \int \frac {\cot (c+d x)+1}{\cot ^2(c+d x)+1}d\sqrt {\cot (c+d x)}\right )}{d \left (a^2+b^2\right )}}{a}-\frac {2 (A b-a B) \sqrt {\cot (c+d x)}}{a d}}{a}-\frac {2 A \cot ^{\frac {3}{2}}(c+d x)}{3 a d}\)

\(\Big \downarrow \) 1476

\(\displaystyle -\frac {-\frac {\frac {b^3 (A b-a B) \int \frac {\tan \left (c+d x+\frac {\pi }{2}\right )^2+1}{\sqrt {-\tan \left (c+d x+\frac {\pi }{2}\right )} \left (b-a \tan \left (c+d x+\frac {\pi }{2}\right )\right )}dx}{a^2+b^2}-\frac {2 a^2 \left (\frac {1}{2} (a (A-B)+b (A+B)) \int \frac {1-\cot (c+d x)}{\cot ^2(c+d x)+1}d\sqrt {\cot (c+d x)}+\frac {1}{2} (b (A-B)-a (A+B)) \left (\frac {1}{2} \int \frac {1}{\cot (c+d x)-\sqrt {2} \sqrt {\cot (c+d x)}+1}d\sqrt {\cot (c+d x)}+\frac {1}{2} \int \frac {1}{\cot (c+d x)+\sqrt {2} \sqrt {\cot (c+d x)}+1}d\sqrt {\cot (c+d x)}\right )\right )}{d \left (a^2+b^2\right )}}{a}-\frac {2 (A b-a B) \sqrt {\cot (c+d x)}}{a d}}{a}-\frac {2 A \cot ^{\frac {3}{2}}(c+d x)}{3 a d}\)

\(\Big \downarrow \) 1082

\(\displaystyle -\frac {-\frac {\frac {b^3 (A b-a B) \int \frac {\tan \left (c+d x+\frac {\pi }{2}\right )^2+1}{\sqrt {-\tan \left (c+d x+\frac {\pi }{2}\right )} \left (b-a \tan \left (c+d x+\frac {\pi }{2}\right )\right )}dx}{a^2+b^2}-\frac {2 a^2 \left (\frac {1}{2} (a (A-B)+b (A+B)) \int \frac {1-\cot (c+d x)}{\cot ^2(c+d x)+1}d\sqrt {\cot (c+d x)}+\frac {1}{2} (b (A-B)-a (A+B)) \left (\frac {\int \frac {1}{-\cot (c+d x)-1}d\left (1-\sqrt {2} \sqrt {\cot (c+d x)}\right )}{\sqrt {2}}-\frac {\int \frac {1}{-\cot (c+d x)-1}d\left (\sqrt {2} \sqrt {\cot (c+d x)}+1\right )}{\sqrt {2}}\right )\right )}{d \left (a^2+b^2\right )}}{a}-\frac {2 (A b-a B) \sqrt {\cot (c+d x)}}{a d}}{a}-\frac {2 A \cot ^{\frac {3}{2}}(c+d x)}{3 a d}\)

\(\Big \downarrow \) 217

\(\displaystyle -\frac {-\frac {\frac {b^3 (A b-a B) \int \frac {\tan \left (c+d x+\frac {\pi }{2}\right )^2+1}{\sqrt {-\tan \left (c+d x+\frac {\pi }{2}\right )} \left (b-a \tan \left (c+d x+\frac {\pi }{2}\right )\right )}dx}{a^2+b^2}-\frac {2 a^2 \left (\frac {1}{2} (a (A-B)+b (A+B)) \int \frac {1-\cot (c+d x)}{\cot ^2(c+d x)+1}d\sqrt {\cot (c+d x)}+\frac {1}{2} (b (A-B)-a (A+B)) \left (\frac {\arctan \left (\sqrt {2} \sqrt {\cot (c+d x)}+1\right )}{\sqrt {2}}-\frac {\arctan \left (1-\sqrt {2} \sqrt {\cot (c+d x)}\right )}{\sqrt {2}}\right )\right )}{d \left (a^2+b^2\right )}}{a}-\frac {2 (A b-a B) \sqrt {\cot (c+d x)}}{a d}}{a}-\frac {2 A \cot ^{\frac {3}{2}}(c+d x)}{3 a d}\)

\(\Big \downarrow \) 1479

\(\displaystyle -\frac {-\frac {\frac {b^3 (A b-a B) \int \frac {\tan \left (c+d x+\frac {\pi }{2}\right )^2+1}{\sqrt {-\tan \left (c+d x+\frac {\pi }{2}\right )} \left (b-a \tan \left (c+d x+\frac {\pi }{2}\right )\right )}dx}{a^2+b^2}-\frac {2 a^2 \left (\frac {1}{2} (a (A-B)+b (A+B)) \left (-\frac {\int -\frac {\sqrt {2}-2 \sqrt {\cot (c+d x)}}{\cot (c+d x)-\sqrt {2} \sqrt {\cot (c+d x)}+1}d\sqrt {\cot (c+d x)}}{2 \sqrt {2}}-\frac {\int -\frac {\sqrt {2} \left (\sqrt {2} \sqrt {\cot (c+d x)}+1\right )}{\cot (c+d x)+\sqrt {2} \sqrt {\cot (c+d x)}+1}d\sqrt {\cot (c+d x)}}{2 \sqrt {2}}\right )+\frac {1}{2} (b (A-B)-a (A+B)) \left (\frac {\arctan \left (\sqrt {2} \sqrt {\cot (c+d x)}+1\right )}{\sqrt {2}}-\frac {\arctan \left (1-\sqrt {2} \sqrt {\cot (c+d x)}\right )}{\sqrt {2}}\right )\right )}{d \left (a^2+b^2\right )}}{a}-\frac {2 (A b-a B) \sqrt {\cot (c+d x)}}{a d}}{a}-\frac {2 A \cot ^{\frac {3}{2}}(c+d x)}{3 a d}\)

\(\Big \downarrow \) 25

\(\displaystyle -\frac {-\frac {\frac {b^3 (A b-a B) \int \frac {\tan \left (c+d x+\frac {\pi }{2}\right )^2+1}{\sqrt {-\tan \left (c+d x+\frac {\pi }{2}\right )} \left (b-a \tan \left (c+d x+\frac {\pi }{2}\right )\right )}dx}{a^2+b^2}-\frac {2 a^2 \left (\frac {1}{2} (a (A-B)+b (A+B)) \left (\frac {\int \frac {\sqrt {2}-2 \sqrt {\cot (c+d x)}}{\cot (c+d x)-\sqrt {2} \sqrt {\cot (c+d x)}+1}d\sqrt {\cot (c+d x)}}{2 \sqrt {2}}+\frac {\int \frac {\sqrt {2} \left (\sqrt {2} \sqrt {\cot (c+d x)}+1\right )}{\cot (c+d x)+\sqrt {2} \sqrt {\cot (c+d x)}+1}d\sqrt {\cot (c+d x)}}{2 \sqrt {2}}\right )+\frac {1}{2} (b (A-B)-a (A+B)) \left (\frac {\arctan \left (\sqrt {2} \sqrt {\cot (c+d x)}+1\right )}{\sqrt {2}}-\frac {\arctan \left (1-\sqrt {2} \sqrt {\cot (c+d x)}\right )}{\sqrt {2}}\right )\right )}{d \left (a^2+b^2\right )}}{a}-\frac {2 (A b-a B) \sqrt {\cot (c+d x)}}{a d}}{a}-\frac {2 A \cot ^{\frac {3}{2}}(c+d x)}{3 a d}\)

\(\Big \downarrow \) 27

\(\displaystyle -\frac {-\frac {\frac {b^3 (A b-a B) \int \frac {\tan \left (c+d x+\frac {\pi }{2}\right )^2+1}{\sqrt {-\tan \left (c+d x+\frac {\pi }{2}\right )} \left (b-a \tan \left (c+d x+\frac {\pi }{2}\right )\right )}dx}{a^2+b^2}-\frac {2 a^2 \left (\frac {1}{2} (a (A-B)+b (A+B)) \left (\frac {\int \frac {\sqrt {2}-2 \sqrt {\cot (c+d x)}}{\cot (c+d x)-\sqrt {2} \sqrt {\cot (c+d x)}+1}d\sqrt {\cot (c+d x)}}{2 \sqrt {2}}+\frac {1}{2} \int \frac {\sqrt {2} \sqrt {\cot (c+d x)}+1}{\cot (c+d x)+\sqrt {2} \sqrt {\cot (c+d x)}+1}d\sqrt {\cot (c+d x)}\right )+\frac {1}{2} (b (A-B)-a (A+B)) \left (\frac {\arctan \left (\sqrt {2} \sqrt {\cot (c+d x)}+1\right )}{\sqrt {2}}-\frac {\arctan \left (1-\sqrt {2} \sqrt {\cot (c+d x)}\right )}{\sqrt {2}}\right )\right )}{d \left (a^2+b^2\right )}}{a}-\frac {2 (A b-a B) \sqrt {\cot (c+d x)}}{a d}}{a}-\frac {2 A \cot ^{\frac {3}{2}}(c+d x)}{3 a d}\)

\(\Big \downarrow \) 1103

\(\displaystyle -\frac {-\frac {\frac {b^3 (A b-a B) \int \frac {\tan \left (c+d x+\frac {\pi }{2}\right )^2+1}{\sqrt {-\tan \left (c+d x+\frac {\pi }{2}\right )} \left (b-a \tan \left (c+d x+\frac {\pi }{2}\right )\right )}dx}{a^2+b^2}-\frac {2 a^2 \left (\frac {1}{2} (b (A-B)-a (A+B)) \left (\frac {\arctan \left (\sqrt {2} \sqrt {\cot (c+d x)}+1\right )}{\sqrt {2}}-\frac {\arctan \left (1-\sqrt {2} \sqrt {\cot (c+d x)}\right )}{\sqrt {2}}\right )+\frac {1}{2} (a (A-B)+b (A+B)) \left (\frac {\log \left (\cot (c+d x)+\sqrt {2} \sqrt {\cot (c+d x)}+1\right )}{2 \sqrt {2}}-\frac {\log \left (\cot (c+d x)-\sqrt {2} \sqrt {\cot (c+d x)}+1\right )}{2 \sqrt {2}}\right )\right )}{d \left (a^2+b^2\right )}}{a}-\frac {2 (A b-a B) \sqrt {\cot (c+d x)}}{a d}}{a}-\frac {2 A \cot ^{\frac {3}{2}}(c+d x)}{3 a d}\)

\(\Big \downarrow \) 4117

\(\displaystyle -\frac {-\frac {\frac {b^3 (A b-a B) \int \frac {1}{\sqrt {\cot (c+d x)} (b+a \cot (c+d x))}d(-\cot (c+d x))}{d \left (a^2+b^2\right )}-\frac {2 a^2 \left (\frac {1}{2} (b (A-B)-a (A+B)) \left (\frac {\arctan \left (\sqrt {2} \sqrt {\cot (c+d x)}+1\right )}{\sqrt {2}}-\frac {\arctan \left (1-\sqrt {2} \sqrt {\cot (c+d x)}\right )}{\sqrt {2}}\right )+\frac {1}{2} (a (A-B)+b (A+B)) \left (\frac {\log \left (\cot (c+d x)+\sqrt {2} \sqrt {\cot (c+d x)}+1\right )}{2 \sqrt {2}}-\frac {\log \left (\cot (c+d x)-\sqrt {2} \sqrt {\cot (c+d x)}+1\right )}{2 \sqrt {2}}\right )\right )}{d \left (a^2+b^2\right )}}{a}-\frac {2 (A b-a B) \sqrt {\cot (c+d x)}}{a d}}{a}-\frac {2 A \cot ^{\frac {3}{2}}(c+d x)}{3 a d}\)

\(\Big \downarrow \) 73

\(\displaystyle -\frac {-\frac {-\frac {2 b^3 (A b-a B) \int \frac {1}{a \cot ^2(c+d x)+b}d\sqrt {\cot (c+d x)}}{d \left (a^2+b^2\right )}-\frac {2 a^2 \left (\frac {1}{2} (b (A-B)-a (A+B)) \left (\frac {\arctan \left (\sqrt {2} \sqrt {\cot (c+d x)}+1\right )}{\sqrt {2}}-\frac {\arctan \left (1-\sqrt {2} \sqrt {\cot (c+d x)}\right )}{\sqrt {2}}\right )+\frac {1}{2} (a (A-B)+b (A+B)) \left (\frac {\log \left (\cot (c+d x)+\sqrt {2} \sqrt {\cot (c+d x)}+1\right )}{2 \sqrt {2}}-\frac {\log \left (\cot (c+d x)-\sqrt {2} \sqrt {\cot (c+d x)}+1\right )}{2 \sqrt {2}}\right )\right )}{d \left (a^2+b^2\right )}}{a}-\frac {2 (A b-a B) \sqrt {\cot (c+d x)}}{a d}}{a}-\frac {2 A \cot ^{\frac {3}{2}}(c+d x)}{3 a d}\)

\(\Big \downarrow \) 218

\(\displaystyle -\frac {-\frac {\frac {2 b^{5/2} (A b-a B) \arctan \left (\frac {\sqrt {a} \cot (c+d x)}{\sqrt {b}}\right )}{\sqrt {a} d \left (a^2+b^2\right )}-\frac {2 a^2 \left (\frac {1}{2} (b (A-B)-a (A+B)) \left (\frac {\arctan \left (\sqrt {2} \sqrt {\cot (c+d x)}+1\right )}{\sqrt {2}}-\frac {\arctan \left (1-\sqrt {2} \sqrt {\cot (c+d x)}\right )}{\sqrt {2}}\right )+\frac {1}{2} (a (A-B)+b (A+B)) \left (\frac {\log \left (\cot (c+d x)+\sqrt {2} \sqrt {\cot (c+d x)}+1\right )}{2 \sqrt {2}}-\frac {\log \left (\cot (c+d x)-\sqrt {2} \sqrt {\cot (c+d x)}+1\right )}{2 \sqrt {2}}\right )\right )}{d \left (a^2+b^2\right )}}{a}-\frac {2 (A b-a B) \sqrt {\cot (c+d x)}}{a d}}{a}-\frac {2 A \cot ^{\frac {3}{2}}(c+d x)}{3 a d}\)

input
Int[(Cot[c + d*x]^(5/2)*(A + B*Tan[c + d*x]))/(a + b*Tan[c + d*x]),x]
 
output
(-2*A*Cot[c + d*x]^(3/2))/(3*a*d) - ((-2*(A*b - a*B)*Sqrt[Cot[c + d*x]])/( 
a*d) - ((2*b^(5/2)*(A*b - a*B)*ArcTan[(Sqrt[a]*Cot[c + d*x])/Sqrt[b]])/(Sq 
rt[a]*(a^2 + b^2)*d) - (2*a^2*(((b*(A - B) - a*(A + B))*(-(ArcTan[1 - Sqrt 
[2]*Sqrt[Cot[c + d*x]]]/Sqrt[2]) + ArcTan[1 + Sqrt[2]*Sqrt[Cot[c + d*x]]]/ 
Sqrt[2]))/2 + ((a*(A - B) + b*(A + B))*(-1/2*Log[1 - Sqrt[2]*Sqrt[Cot[c + 
d*x]] + Cot[c + d*x]]/Sqrt[2] + Log[1 + Sqrt[2]*Sqrt[Cot[c + d*x]] + Cot[c 
 + d*x]]/(2*Sqrt[2])))/2))/((a^2 + b^2)*d))/a)/a
 

3.6.89.3.1 Defintions of rubi rules used

rule 25
Int[-(Fx_), x_Symbol] :> Simp[Identity[-1]   Int[Fx, x], x]
 

rule 27
Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 73
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[ 
{p = Denominator[m]}, Simp[p/b   Subst[Int[x^(p*(m + 1) - 1)*(c - a*(d/b) + 
 d*(x^p/b))^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] && Lt 
Q[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntL 
inearQ[a, b, c, d, m, n, x]
 

rule 217
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(-(Rt[-a, 2]*Rt[-b, 2])^( 
-1))*ArcTan[Rt[-b, 2]*(x/Rt[-a, 2])], x] /; FreeQ[{a, b}, x] && PosQ[a/b] & 
& (LtQ[a, 0] || LtQ[b, 0])
 

rule 218
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[a/b, 2]/a)*ArcTan[x/R 
t[a/b, 2]], x] /; FreeQ[{a, b}, x] && PosQ[a/b]
 

rule 1082
Int[((a_) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> With[{q = 1 - 4*S 
implify[a*(c/b^2)]}, Simp[-2/b   Subst[Int[1/(q - x^2), x], x, 1 + 2*c*(x/b 
)], x] /; RationalQ[q] && (EqQ[q^2, 1] ||  !RationalQ[b^2 - 4*a*c])] /; Fre 
eQ[{a, b, c}, x]
 

rule 1103
Int[((d_) + (e_.)*(x_))/((a_.) + (b_.)*(x_) + (c_.)*(x_)^2), x_Symbol] :> S 
imp[d*(Log[RemoveContent[a + b*x + c*x^2, x]]/b), x] /; FreeQ[{a, b, c, d, 
e}, x] && EqQ[2*c*d - b*e, 0]
 

rule 1476
Int[((d_) + (e_.)*(x_)^2)/((a_) + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[ 
2*(d/e), 2]}, Simp[e/(2*c)   Int[1/Simp[d/e + q*x + x^2, x], x], x] + Simp[ 
e/(2*c)   Int[1/Simp[d/e - q*x + x^2, x], x], x]] /; FreeQ[{a, c, d, e}, x] 
 && EqQ[c*d^2 - a*e^2, 0] && PosQ[d*e]
 

rule 1479
Int[((d_) + (e_.)*(x_)^2)/((a_) + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[ 
-2*(d/e), 2]}, Simp[e/(2*c*q)   Int[(q - 2*x)/Simp[d/e + q*x - x^2, x], x], 
 x] + Simp[e/(2*c*q)   Int[(q + 2*x)/Simp[d/e - q*x - x^2, x], x], x]] /; F 
reeQ[{a, c, d, e}, x] && EqQ[c*d^2 - a*e^2, 0] && NegQ[d*e]
 

rule 1482
Int[((d_) + (e_.)*(x_)^2)/((a_) + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[ 
a*c, 2]}, Simp[(d*q + a*e)/(2*a*c)   Int[(q + c*x^2)/(a + c*x^4), x], x] + 
Simp[(d*q - a*e)/(2*a*c)   Int[(q - c*x^2)/(a + c*x^4), x], x]] /; FreeQ[{a 
, c, d, e}, x] && NeQ[c*d^2 + a*e^2, 0] && NeQ[c*d^2 - a*e^2, 0] && NegQ[(- 
a)*c]
 

rule 3042
Int[u_, x_Symbol] :> Int[DeactivateTrig[u, x], x] /; FunctionOfTrigOfLinear 
Q[u, x]
 

rule 4017
Int[((c_) + (d_.)*tan[(e_.) + (f_.)*(x_)])/Sqrt[(b_.)*tan[(e_.) + (f_.)*(x_ 
)]], x_Symbol] :> Simp[2/f   Subst[Int[(b*c + d*x^2)/(b^2 + x^4), x], x, Sq 
rt[b*Tan[e + f*x]]], x] /; FreeQ[{b, c, d, e, f}, x] && NeQ[c^2 - d^2, 0] & 
& NeQ[c^2 + d^2, 0]
 

rule 4064
Int[(cot[(e_.) + (f_.)*(x_)]*(g_.))^(p_)*((a_.) + (b_.)*tan[(e_.) + (f_.)*( 
x_)])^(m_.)*((c_) + (d_.)*tan[(e_.) + (f_.)*(x_)])^(n_.), x_Symbol] :> Simp 
[g^(m + n)   Int[(g*Cot[e + f*x])^(p - m - n)*(b + a*Cot[e + f*x])^m*(d + c 
*Cot[e + f*x])^n, x], x] /; FreeQ[{a, b, c, d, e, f, g, p}, x] &&  !Integer 
Q[p] && IntegerQ[m] && IntegerQ[n]
 

rule 4090
Int[((a_.) + (b_.)*tan[(e_.) + (f_.)*(x_)])^(m_)*((A_.) + (B_.)*tan[(e_.) + 
 (f_.)*(x_)])*((c_.) + (d_.)*tan[(e_.) + (f_.)*(x_)])^(n_), x_Symbol] :> Si 
mp[b*B*(a + b*Tan[e + f*x])^(m - 1)*((c + d*Tan[e + f*x])^(n + 1)/(d*f*(m + 
 n))), x] + Simp[1/(d*(m + n))   Int[(a + b*Tan[e + f*x])^(m - 2)*(c + d*Ta 
n[e + f*x])^n*Simp[a^2*A*d*(m + n) - b*B*(b*c*(m - 1) + a*d*(n + 1)) + d*(m 
 + n)*(2*a*A*b + B*(a^2 - b^2))*Tan[e + f*x] - (b*B*(b*c - a*d)*(m - 1) - b 
*(A*b + a*B)*d*(m + n))*Tan[e + f*x]^2, x], x], x] /; FreeQ[{a, b, c, d, e, 
 f, A, B, n}, x] && NeQ[b*c - a*d, 0] && NeQ[a^2 + b^2, 0] && NeQ[c^2 + d^2 
, 0] && GtQ[m, 1] && (IntegerQ[m] || IntegersQ[2*m, 2*n]) &&  !(IGtQ[n, 1] 
&& ( !IntegerQ[m] || (EqQ[c, 0] && NeQ[a, 0])))
 

rule 4117
Int[((a_.) + (b_.)*tan[(e_.) + (f_.)*(x_)])^(m_.)*((c_.) + (d_.)*tan[(e_.) 
+ (f_.)*(x_)])^(n_.)*((A_) + (C_.)*tan[(e_.) + (f_.)*(x_)]^2), x_Symbol] :> 
 Simp[A/f   Subst[Int[(a + b*x)^m*(c + d*x)^n, x], x, Tan[e + f*x]], x] /; 
FreeQ[{a, b, c, d, e, f, A, C, m, n}, x] && EqQ[A, C]
 

rule 4130
Int[((a_.) + (b_.)*tan[(e_.) + (f_.)*(x_)])^(m_.)*((c_.) + (d_.)*tan[(e_.) 
+ (f_.)*(x_)])^(n_)*((A_.) + (B_.)*tan[(e_.) + (f_.)*(x_)] + (C_.)*tan[(e_. 
) + (f_.)*(x_)]^2), x_Symbol] :> Simp[C*(a + b*Tan[e + f*x])^m*((c + d*Tan[ 
e + f*x])^(n + 1)/(d*f*(m + n + 1))), x] + Simp[1/(d*(m + n + 1))   Int[(a 
+ b*Tan[e + f*x])^(m - 1)*(c + d*Tan[e + f*x])^n*Simp[a*A*d*(m + n + 1) - C 
*(b*c*m + a*d*(n + 1)) + d*(A*b + a*B - b*C)*(m + n + 1)*Tan[e + f*x] - (C* 
m*(b*c - a*d) - b*B*d*(m + n + 1))*Tan[e + f*x]^2, x], x], x] /; FreeQ[{a, 
b, c, d, e, f, A, B, C, n}, x] && NeQ[b*c - a*d, 0] && NeQ[a^2 + b^2, 0] && 
 NeQ[c^2 + d^2, 0] && GtQ[m, 0] &&  !(IGtQ[n, 0] && ( !IntegerQ[m] || (EqQ[ 
c, 0] && NeQ[a, 0])))
 

rule 4136
Int[(((c_.) + (d_.)*tan[(e_.) + (f_.)*(x_)])^(n_)*((A_.) + (B_.)*tan[(e_.) 
+ (f_.)*(x_)] + (C_.)*tan[(e_.) + (f_.)*(x_)]^2))/((a_.) + (b_.)*tan[(e_.) 
+ (f_.)*(x_)]), x_Symbol] :> Simp[1/(a^2 + b^2)   Int[(c + d*Tan[e + f*x])^ 
n*Simp[b*B + a*(A - C) + (a*B - b*(A - C))*Tan[e + f*x], x], x], x] + Simp[ 
(A*b^2 - a*b*B + a^2*C)/(a^2 + b^2)   Int[(c + d*Tan[e + f*x])^n*((1 + Tan[ 
e + f*x]^2)/(a + b*Tan[e + f*x])), x], x] /; FreeQ[{a, b, c, d, e, f, A, B, 
 C, n}, x] && NeQ[b*c - a*d, 0] && NeQ[a^2 + b^2, 0] && NeQ[c^2 + d^2, 0] & 
&  !GtQ[n, 0] &&  !LeQ[n, -1]
 
3.6.89.4 Maple [B] (verified)

Leaf count of result is larger than twice the leaf count of optimal. \(771\) vs. \(2(281)=562\).

Time = 0.50 (sec) , antiderivative size = 772, normalized size of antiderivative = 2.38

method result size
derivativedivides \(-\frac {\left (\frac {1}{\tan \left (d x +c \right )}\right )^{\frac {5}{2}} \tan \left (d x +c \right ) \left (3 A \tan \left (d x +c \right )^{\frac {3}{2}} \sqrt {2}\, \sqrt {a b}\, \ln \left (-\frac {1+\sqrt {2}\, \sqrt {\tan \left (d x +c \right )}+\tan \left (d x +c \right )}{\sqrt {2}\, \sqrt {\tan \left (d x +c \right )}-\tan \left (d x +c \right )-1}\right ) a^{3}+6 A \tan \left (d x +c \right )^{\frac {3}{2}} \sqrt {2}\, \sqrt {a b}\, \arctan \left (1+\sqrt {2}\, \sqrt {\tan \left (d x +c \right )}\right ) a^{3}-6 A \tan \left (d x +c \right )^{\frac {3}{2}} \sqrt {2}\, \sqrt {a b}\, \arctan \left (1+\sqrt {2}\, \sqrt {\tan \left (d x +c \right )}\right ) a^{2} b +6 A \tan \left (d x +c \right )^{\frac {3}{2}} \sqrt {2}\, \sqrt {a b}\, \arctan \left (-1+\sqrt {2}\, \sqrt {\tan \left (d x +c \right )}\right ) a^{3}-6 A \tan \left (d x +c \right )^{\frac {3}{2}} \sqrt {2}\, \sqrt {a b}\, \arctan \left (-1+\sqrt {2}\, \sqrt {\tan \left (d x +c \right )}\right ) a^{2} b -3 A \tan \left (d x +c \right )^{\frac {3}{2}} \sqrt {2}\, \sqrt {a b}\, \ln \left (-\frac {\sqrt {2}\, \sqrt {\tan \left (d x +c \right )}-\tan \left (d x +c \right )-1}{1+\sqrt {2}\, \sqrt {\tan \left (d x +c \right )}+\tan \left (d x +c \right )}\right ) a^{2} b +3 B \tan \left (d x +c \right )^{\frac {3}{2}} \sqrt {2}\, \sqrt {a b}\, \ln \left (-\frac {1+\sqrt {2}\, \sqrt {\tan \left (d x +c \right )}+\tan \left (d x +c \right )}{\sqrt {2}\, \sqrt {\tan \left (d x +c \right )}-\tan \left (d x +c \right )-1}\right ) a^{2} b +6 B \tan \left (d x +c \right )^{\frac {3}{2}} \sqrt {2}\, \sqrt {a b}\, \arctan \left (1+\sqrt {2}\, \sqrt {\tan \left (d x +c \right )}\right ) a^{3}+6 B \tan \left (d x +c \right )^{\frac {3}{2}} \sqrt {2}\, \sqrt {a b}\, \arctan \left (1+\sqrt {2}\, \sqrt {\tan \left (d x +c \right )}\right ) a^{2} b +6 B \tan \left (d x +c \right )^{\frac {3}{2}} \sqrt {2}\, \sqrt {a b}\, \arctan \left (-1+\sqrt {2}\, \sqrt {\tan \left (d x +c \right )}\right ) a^{3}+6 B \tan \left (d x +c \right )^{\frac {3}{2}} \sqrt {2}\, \sqrt {a b}\, \arctan \left (-1+\sqrt {2}\, \sqrt {\tan \left (d x +c \right )}\right ) a^{2} b +3 B \tan \left (d x +c \right )^{\frac {3}{2}} \sqrt {2}\, \sqrt {a b}\, \ln \left (-\frac {\sqrt {2}\, \sqrt {\tan \left (d x +c \right )}-\tan \left (d x +c \right )-1}{1+\sqrt {2}\, \sqrt {\tan \left (d x +c \right )}+\tan \left (d x +c \right )}\right ) a^{3}-24 A \tan \left (d x +c \right )^{\frac {3}{2}} \arctan \left (\frac {b \sqrt {\tan \left (d x +c \right )}}{\sqrt {a b}}\right ) b^{4}+24 B \tan \left (d x +c \right )^{\frac {3}{2}} \arctan \left (\frac {b \sqrt {\tan \left (d x +c \right )}}{\sqrt {a b}}\right ) a \,b^{3}-24 A \tan \left (d x +c \right ) \sqrt {a b}\, a^{2} b -24 A \tan \left (d x +c \right ) \sqrt {a b}\, b^{3}+24 B \tan \left (d x +c \right ) \sqrt {a b}\, a^{3}+24 B \tan \left (d x +c \right ) \sqrt {a b}\, a \,b^{2}+8 A \sqrt {a b}\, a^{3}+8 A \sqrt {a b}\, a \,b^{2}\right )}{12 d \,a^{2} \left (a^{2}+b^{2}\right ) \sqrt {a b}}\) \(772\)
default \(-\frac {\left (\frac {1}{\tan \left (d x +c \right )}\right )^{\frac {5}{2}} \tan \left (d x +c \right ) \left (3 A \tan \left (d x +c \right )^{\frac {3}{2}} \sqrt {2}\, \sqrt {a b}\, \ln \left (-\frac {1+\sqrt {2}\, \sqrt {\tan \left (d x +c \right )}+\tan \left (d x +c \right )}{\sqrt {2}\, \sqrt {\tan \left (d x +c \right )}-\tan \left (d x +c \right )-1}\right ) a^{3}+6 A \tan \left (d x +c \right )^{\frac {3}{2}} \sqrt {2}\, \sqrt {a b}\, \arctan \left (1+\sqrt {2}\, \sqrt {\tan \left (d x +c \right )}\right ) a^{3}-6 A \tan \left (d x +c \right )^{\frac {3}{2}} \sqrt {2}\, \sqrt {a b}\, \arctan \left (1+\sqrt {2}\, \sqrt {\tan \left (d x +c \right )}\right ) a^{2} b +6 A \tan \left (d x +c \right )^{\frac {3}{2}} \sqrt {2}\, \sqrt {a b}\, \arctan \left (-1+\sqrt {2}\, \sqrt {\tan \left (d x +c \right )}\right ) a^{3}-6 A \tan \left (d x +c \right )^{\frac {3}{2}} \sqrt {2}\, \sqrt {a b}\, \arctan \left (-1+\sqrt {2}\, \sqrt {\tan \left (d x +c \right )}\right ) a^{2} b -3 A \tan \left (d x +c \right )^{\frac {3}{2}} \sqrt {2}\, \sqrt {a b}\, \ln \left (-\frac {\sqrt {2}\, \sqrt {\tan \left (d x +c \right )}-\tan \left (d x +c \right )-1}{1+\sqrt {2}\, \sqrt {\tan \left (d x +c \right )}+\tan \left (d x +c \right )}\right ) a^{2} b +3 B \tan \left (d x +c \right )^{\frac {3}{2}} \sqrt {2}\, \sqrt {a b}\, \ln \left (-\frac {1+\sqrt {2}\, \sqrt {\tan \left (d x +c \right )}+\tan \left (d x +c \right )}{\sqrt {2}\, \sqrt {\tan \left (d x +c \right )}-\tan \left (d x +c \right )-1}\right ) a^{2} b +6 B \tan \left (d x +c \right )^{\frac {3}{2}} \sqrt {2}\, \sqrt {a b}\, \arctan \left (1+\sqrt {2}\, \sqrt {\tan \left (d x +c \right )}\right ) a^{3}+6 B \tan \left (d x +c \right )^{\frac {3}{2}} \sqrt {2}\, \sqrt {a b}\, \arctan \left (1+\sqrt {2}\, \sqrt {\tan \left (d x +c \right )}\right ) a^{2} b +6 B \tan \left (d x +c \right )^{\frac {3}{2}} \sqrt {2}\, \sqrt {a b}\, \arctan \left (-1+\sqrt {2}\, \sqrt {\tan \left (d x +c \right )}\right ) a^{3}+6 B \tan \left (d x +c \right )^{\frac {3}{2}} \sqrt {2}\, \sqrt {a b}\, \arctan \left (-1+\sqrt {2}\, \sqrt {\tan \left (d x +c \right )}\right ) a^{2} b +3 B \tan \left (d x +c \right )^{\frac {3}{2}} \sqrt {2}\, \sqrt {a b}\, \ln \left (-\frac {\sqrt {2}\, \sqrt {\tan \left (d x +c \right )}-\tan \left (d x +c \right )-1}{1+\sqrt {2}\, \sqrt {\tan \left (d x +c \right )}+\tan \left (d x +c \right )}\right ) a^{3}-24 A \tan \left (d x +c \right )^{\frac {3}{2}} \arctan \left (\frac {b \sqrt {\tan \left (d x +c \right )}}{\sqrt {a b}}\right ) b^{4}+24 B \tan \left (d x +c \right )^{\frac {3}{2}} \arctan \left (\frac {b \sqrt {\tan \left (d x +c \right )}}{\sqrt {a b}}\right ) a \,b^{3}-24 A \tan \left (d x +c \right ) \sqrt {a b}\, a^{2} b -24 A \tan \left (d x +c \right ) \sqrt {a b}\, b^{3}+24 B \tan \left (d x +c \right ) \sqrt {a b}\, a^{3}+24 B \tan \left (d x +c \right ) \sqrt {a b}\, a \,b^{2}+8 A \sqrt {a b}\, a^{3}+8 A \sqrt {a b}\, a \,b^{2}\right )}{12 d \,a^{2} \left (a^{2}+b^{2}\right ) \sqrt {a b}}\) \(772\)

input
int(cot(d*x+c)^(5/2)*(A+B*tan(d*x+c))/(a+b*tan(d*x+c)),x,method=_RETURNVER 
BOSE)
 
output
-1/12/d*(1/tan(d*x+c))^(5/2)*tan(d*x+c)*(3*A*tan(d*x+c)^(3/2)*2^(1/2)*(a*b 
)^(1/2)*ln(-(1+2^(1/2)*tan(d*x+c)^(1/2)+tan(d*x+c))/(2^(1/2)*tan(d*x+c)^(1 
/2)-tan(d*x+c)-1))*a^3+6*A*tan(d*x+c)^(3/2)*2^(1/2)*(a*b)^(1/2)*arctan(1+2 
^(1/2)*tan(d*x+c)^(1/2))*a^3-6*A*tan(d*x+c)^(3/2)*2^(1/2)*(a*b)^(1/2)*arct 
an(1+2^(1/2)*tan(d*x+c)^(1/2))*a^2*b+6*A*tan(d*x+c)^(3/2)*2^(1/2)*(a*b)^(1 
/2)*arctan(-1+2^(1/2)*tan(d*x+c)^(1/2))*a^3-6*A*tan(d*x+c)^(3/2)*2^(1/2)*( 
a*b)^(1/2)*arctan(-1+2^(1/2)*tan(d*x+c)^(1/2))*a^2*b-3*A*tan(d*x+c)^(3/2)* 
2^(1/2)*(a*b)^(1/2)*ln(-(2^(1/2)*tan(d*x+c)^(1/2)-tan(d*x+c)-1)/(1+2^(1/2) 
*tan(d*x+c)^(1/2)+tan(d*x+c)))*a^2*b+3*B*tan(d*x+c)^(3/2)*2^(1/2)*(a*b)^(1 
/2)*ln(-(1+2^(1/2)*tan(d*x+c)^(1/2)+tan(d*x+c))/(2^(1/2)*tan(d*x+c)^(1/2)- 
tan(d*x+c)-1))*a^2*b+6*B*tan(d*x+c)^(3/2)*2^(1/2)*(a*b)^(1/2)*arctan(1+2^( 
1/2)*tan(d*x+c)^(1/2))*a^3+6*B*tan(d*x+c)^(3/2)*2^(1/2)*(a*b)^(1/2)*arctan 
(1+2^(1/2)*tan(d*x+c)^(1/2))*a^2*b+6*B*tan(d*x+c)^(3/2)*2^(1/2)*(a*b)^(1/2 
)*arctan(-1+2^(1/2)*tan(d*x+c)^(1/2))*a^3+6*B*tan(d*x+c)^(3/2)*2^(1/2)*(a* 
b)^(1/2)*arctan(-1+2^(1/2)*tan(d*x+c)^(1/2))*a^2*b+3*B*tan(d*x+c)^(3/2)*2^ 
(1/2)*(a*b)^(1/2)*ln(-(2^(1/2)*tan(d*x+c)^(1/2)-tan(d*x+c)-1)/(1+2^(1/2)*t 
an(d*x+c)^(1/2)+tan(d*x+c)))*a^3-24*A*tan(d*x+c)^(3/2)*arctan(b*tan(d*x+c) 
^(1/2)/(a*b)^(1/2))*b^4+24*B*tan(d*x+c)^(3/2)*arctan(b*tan(d*x+c)^(1/2)/(a 
*b)^(1/2))*a*b^3-24*A*tan(d*x+c)*(a*b)^(1/2)*a^2*b-24*A*tan(d*x+c)*(a*b)^( 
1/2)*b^3+24*B*tan(d*x+c)*(a*b)^(1/2)*a^3+24*B*tan(d*x+c)*(a*b)^(1/2)*a*...
 
3.6.89.5 Fricas [B] (verification not implemented)

Leaf count of result is larger than twice the leaf count of optimal. 3115 vs. \(2 (281) = 562\).

Time = 26.27 (sec) , antiderivative size = 6260, normalized size of antiderivative = 19.26 \[ \int \frac {\cot ^{\frac {5}{2}}(c+d x) (A+B \tan (c+d x))}{a+b \tan (c+d x)} \, dx=\text {Too large to display} \]

input
integrate(cot(d*x+c)^(5/2)*(A+B*tan(d*x+c))/(a+b*tan(d*x+c)),x, algorithm= 
"fricas")
 
output
Too large to include
 
3.6.89.6 Sympy [F(-1)]

Timed out. \[ \int \frac {\cot ^{\frac {5}{2}}(c+d x) (A+B \tan (c+d x))}{a+b \tan (c+d x)} \, dx=\text {Timed out} \]

input
integrate(cot(d*x+c)**(5/2)*(A+B*tan(d*x+c))/(a+b*tan(d*x+c)),x)
 
output
Timed out
 
3.6.89.7 Maxima [A] (verification not implemented)

Time = 0.31 (sec) , antiderivative size = 262, normalized size of antiderivative = 0.81 \[ \int \frac {\cot ^{\frac {5}{2}}(c+d x) (A+B \tan (c+d x))}{a+b \tan (c+d x)} \, dx=\frac {\frac {24 \, {\left (B a b^{3} - A b^{4}\right )} \arctan \left (\frac {a}{\sqrt {a b} \sqrt {\tan \left (d x + c\right )}}\right )}{{\left (a^{4} + a^{2} b^{2}\right )} \sqrt {a b}} + \frac {3 \, {\left (2 \, \sqrt {2} {\left ({\left (A + B\right )} a - {\left (A - B\right )} b\right )} \arctan \left (\frac {1}{2} \, \sqrt {2} {\left (\sqrt {2} + \frac {2}{\sqrt {\tan \left (d x + c\right )}}\right )}\right ) + 2 \, \sqrt {2} {\left ({\left (A + B\right )} a - {\left (A - B\right )} b\right )} \arctan \left (-\frac {1}{2} \, \sqrt {2} {\left (\sqrt {2} - \frac {2}{\sqrt {\tan \left (d x + c\right )}}\right )}\right ) - \sqrt {2} {\left ({\left (A - B\right )} a + {\left (A + B\right )} b\right )} \log \left (\frac {\sqrt {2}}{\sqrt {\tan \left (d x + c\right )}} + \frac {1}{\tan \left (d x + c\right )} + 1\right ) + \sqrt {2} {\left ({\left (A - B\right )} a + {\left (A + B\right )} b\right )} \log \left (-\frac {\sqrt {2}}{\sqrt {\tan \left (d x + c\right )}} + \frac {1}{\tan \left (d x + c\right )} + 1\right )\right )}}{a^{2} + b^{2}} - \frac {8 \, {\left (\frac {A a}{\tan \left (d x + c\right )^{\frac {3}{2}}} + \frac {3 \, {\left (B a - A b\right )}}{\sqrt {\tan \left (d x + c\right )}}\right )}}{a^{2}}}{12 \, d} \]

input
integrate(cot(d*x+c)^(5/2)*(A+B*tan(d*x+c))/(a+b*tan(d*x+c)),x, algorithm= 
"maxima")
 
output
1/12*(24*(B*a*b^3 - A*b^4)*arctan(a/(sqrt(a*b)*sqrt(tan(d*x + c))))/((a^4 
+ a^2*b^2)*sqrt(a*b)) + 3*(2*sqrt(2)*((A + B)*a - (A - B)*b)*arctan(1/2*sq 
rt(2)*(sqrt(2) + 2/sqrt(tan(d*x + c)))) + 2*sqrt(2)*((A + B)*a - (A - B)*b 
)*arctan(-1/2*sqrt(2)*(sqrt(2) - 2/sqrt(tan(d*x + c)))) - sqrt(2)*((A - B) 
*a + (A + B)*b)*log(sqrt(2)/sqrt(tan(d*x + c)) + 1/tan(d*x + c) + 1) + sqr 
t(2)*((A - B)*a + (A + B)*b)*log(-sqrt(2)/sqrt(tan(d*x + c)) + 1/tan(d*x + 
 c) + 1))/(a^2 + b^2) - 8*(A*a/tan(d*x + c)^(3/2) + 3*(B*a - A*b)/sqrt(tan 
(d*x + c)))/a^2)/d
 
3.6.89.8 Giac [F]

\[ \int \frac {\cot ^{\frac {5}{2}}(c+d x) (A+B \tan (c+d x))}{a+b \tan (c+d x)} \, dx=\int { \frac {{\left (B \tan \left (d x + c\right ) + A\right )} \cot \left (d x + c\right )^{\frac {5}{2}}}{b \tan \left (d x + c\right ) + a} \,d x } \]

input
integrate(cot(d*x+c)^(5/2)*(A+B*tan(d*x+c))/(a+b*tan(d*x+c)),x, algorithm= 
"giac")
 
output
integrate((B*tan(d*x + c) + A)*cot(d*x + c)^(5/2)/(b*tan(d*x + c) + a), x)
 
3.6.89.9 Mupad [F(-1)]

Timed out. \[ \int \frac {\cot ^{\frac {5}{2}}(c+d x) (A+B \tan (c+d x))}{a+b \tan (c+d x)} \, dx=\int \frac {{\mathrm {cot}\left (c+d\,x\right )}^{5/2}\,\left (A+B\,\mathrm {tan}\left (c+d\,x\right )\right )}{a+b\,\mathrm {tan}\left (c+d\,x\right )} \,d x \]

input
int((cot(c + d*x)^(5/2)*(A + B*tan(c + d*x)))/(a + b*tan(c + d*x)),x)
 
output
int((cot(c + d*x)^(5/2)*(A + B*tan(c + d*x)))/(a + b*tan(c + d*x)), x)